<!DOCTYPE html>
<!-- KaTeX requires the use of the HTML5 doctype. Without it, KaTeX may not render properly -->
<html>
	<head>
		<link rel="stylesheet" href="katex/katex.min.css">
		<script src="katex/katex.min.js"></script>
		<script src="katex/contrib/auto-render.js"></script>
		<script>
			//等待DOM加载完成后渲染，避免影响页面加载时间
			window.onload = function() {
				var str = document.getElementById("math");  //这里根据不同主题调整
				var isKaTex = str.innerHTML.indexOf('$');  //以是否存在 “$”来判断LaTeX公式，可能有误判情况
				if(isKaTex != -1){
					renderMathInElement(str,{delimiters: [
						{left: "$$", right: "$$", display: true},
						{left: "\\[", right: "\\]", display: true},
						{left: "$", right: "$", display: false},
						{left: "\\(", right: "\\)", display: false}
					]});
				}
			}
		</script>
	</head>
<body>
<div style="width:500px; margin: 0 auto;font-size:25px;text-align: center">行内的公式 Inline</div>
<div id="math">
	$$E=mc^2$$

	$$E=mc^2$$

	$$c = \pm\sqrt{a^2 + b^2}$$

	$$x > y$$

	$$f(x) = x^2$$

	$$\alpha = \sqrt{1-e^2}$$

	$$(\sqrt{3x-1}+(1+x)^2)$$

	$$\sin(\alpha)^{\theta}=\sum_{i=0}^{n}(x^i + \cos(f))$$

	$$\dfrac{-b \pm \sqrt{b^2 - 4ac}}{2a}$$

	$$f(x) = \int_{-\infty}^\infty\hat f(\xi)\,e^{2 \pi i \xi x}\,d\xi$$

	$$\displaystyle \frac{1}{\Bigl(\sqrt{\phi \sqrt{5}}-\phi\Bigr) e^{\frac25 \pi}} = 1+\frac{e^{-2\pi}} {1+\frac{e^{-4\pi}} {1+\frac{e^{-6\pi}} {1+\frac{e^{-8\pi}} {1+\cdots} } } }$$

	$$\displaystyle \left( \sum\_{k=1}^n a\_k b\_k \right)^2 \leq \left( \sum\_{k=1}^n a\_k^2 \right) \left( \sum\_{k=1}^n b\_k^2 \right)$$

	$$a^2$$

	$$a^{2+2}$$

	$$a_2$$

	$${x_2}^3$$

	$$x_2^3$$

	$$10^{10^{8}}$$

	$$a_{i,j}$$

	$$_nP_k$$

	$$c = \pm\sqrt{a^2 + b^2}$$

	$$\frac{1}{2}=0.5$$

	$$\dfrac{k}{k-1} = 0.5$$

	$$\dbinom{n}{k} \binom{n}{k}$$

	$$\oint_C x^3\, dx + 4y^2\, dy$$

	$$\bigcap_1^n p   \bigcup_1^k p$$

	$$e^{i \pi} + 1 = 0$$

	$$\left ( \frac{1}{2} \right )$$

	$$x_{1,2}=\frac{-b\pm\sqrt{\color{Red}b^2-4ac}}{2a}$$

	$${\color{Blue}x^2}+{\color{YellowOrange}2x}-{\color{OliveGreen}1}$$

	$$\textstyle \sum_{k=1}^N k^2$$

	$$\dfrac{ \tfrac{1}{2}[1-(\tfrac{1}{2})^n] }{ 1-\tfrac{1}{2} } = s_n$$

	$$\binom{n}{k}$$

	$$0+1+2+3+4+5+6+7+8+9+10+11+12+13+14+15+16+17+18+19+20+\cdots$$

	$$\sum_{k=1}^N k^2$$

	$$\textstyle \sum_{k=1}^N k^2$$

	$$\prod_{i=1}^N x_i$$

	$$\textstyle \prod_{i=1}^N x_i$$

	$$\coprod_{i=1}^N x_i$$

	$$\textstyle \coprod_{i=1}^N x_i$$

	$$\int_{1}^{3}\frac{e^3/x}{x^2}\, dx$$

	$$\int_C x^3\, dx + 4y^2\, dy$$

	$${}_1^2\!\Omega_3^4$$
</div>
</body>  
</html>